1 calorie = 4.186 J. Latent heat of vaporization of water = 539 cal/g = 2256 kJ/kg. Latent heat of fusion of water = 79.5 cal/g = 333 kJ/kg. Specific heat of water = 1 cal/g = 4.19 kJ/kg.
In this manner, what is the heat of vaporization of water in calories per gram?
Similarly, while ice melts, it remains at 0 °C (32 °F), and the liquid water that is formed with the latent heat of fusion is also at 0 °C. The heat of fusion for water at 0 °C is approximately 334 joules (79.7 calories) per gram, and the heat of vaporization at 100 °C is about 2,230 joules (533 calories) per gram.
Why is a steam burn more damaging than a burn from boiling water at the same temperature?
Phase changes require a lot more energy than just a temperature change. The energy required for water to go from a liquid to a gas is called the heat of vaporization. When steam (water in the gas phase) hits your skin, a lot of energy will be released as it condenses into a liquid, undergoing a phase change.
How many joules of energy does it take to melt ice?
Problem 2 - The Latent Heat of Fusion for water is 333 Joules/gram. How many Joules of energy do you need to melt all the ice into a pure liquid along the path from B to C on the graph? Answer: For 1 kilogram of ice ,which equals 1000 grams, we need 333 Joules/gram x 1000 grams = 333,000 Joules.