1 calorie =

**4.186 J**. Latent heat of vaporization of water = 539 cal/g =**2256 kJ/kg**. Latent heat of fusion of water =**79.5**cal/g =**333 kJ/kg**. Specific heat of water = 1 cal/g = 4.19 kJ/kg.In this manner, what is the heat of vaporization of water in calories per gram?

Similarly, while

**ice**melts, it remains at 0 °C (32 °F), and the liquid water that is formed with the latent heat of fusion is also at 0 °C. The heat of fusion for water at 0 °C is approximately 334 joules (79.7 calories) per gram, and the heat of vaporization at 100 °C is about 2,230 joules (533 calories) per gram.Why is a steam burn more damaging than a burn from boiling water at the same temperature?

Phase changes require a lot

**more**energy**than**just a temperature change. The energy required for**water**to go from a liquid to a gas is called the heat of vaporization. When**steam**(**water**in the gas phase) hits your skin, a lot of energy will be released as it condenses into a liquid, undergoing a phase change.How many joules of energy does it take to melt ice?

Problem 2 - The Latent Heat of Fusion for water is

**333 Joules**/gram. How many Joules of energy do you need to melt all the ice into a pure liquid along the path from B to C on the graph? Answer: For 1 kilogram of ice ,which equals 1000 grams, we need**333 Joules**/gram x 1000 grams =**333,000 Joules**.