(1,

**0**) = (x, y) = (cos**0**,**sin 0**), cos**0**= 1,**sin 0**=**0**. The values of angles outside Quadrant I can be computed using reference angles, and the values of the other trigonometric functions can be computed using the reciprocal and quotient identities.Furthermore, why is it impossible for sin to be greater than 1?

The hypotenuse in a right triangle is always

**larger than**the opposite side, so for angles**greater than**zero but less**than**90º the**sine**ratio**will**be less**than 1**. For angles outside of these limits, the**sine**ratio**can**have values from -**1**to**1**.Is inverse sine the same as 1 sin?

That's actually a logical choice, since

^{−}**is the standard way to designate an**^{1}**inverse**function. But the problem is that it makes you want to think of**sin**^{−}**(x) as**^{1}**1**/**sin**(x), even though they're not the same at all. Many calculators use**sin**^{−}**for the function name, though some use lower-case arcsin.**^{1}What is tan to the negative 1?

The Value of the Inverse Tan of 1. As you can see below, the inverse tan

^{-}^{1}(1) is 45° or, in radian measure, Π/4. It is helpful to think of tangent as the ratio of**sine**over**cosine**, ie: . Therefore, tan(Θ) to equal 1,**sin**(Θ) and**cos**(Θ) must have the same value.