Originally Answered: What is the

**bond order**of**F2**?**Bond order**is defined as the difference between the number of**bonding**electrons divided by 2, and the number of anti-**bonding**electrons divided by 2. Fluorine molecule,**F2**, has 18 electrons in total. It has 10**bonding**electrons and 8 antibonding electrons.Moreover, is c2 4 paramagnetic or diamagnetic?

Answers : (1) B

_{2}has 2 unpaired electron so it is predicted to be**paramagnetic**whereas C_{2}has only paired electrons so it is predicted to be**diamagnetic**but not**paramagnetic**.Why b2 molecule is paramagnetic?

By constructing a molecular orbital picture for each of the following molecules, determine whether it is

**paramagnetic**or diamagnetic. a. B_{2}is**paramagnetic**because it has two unpaired electrons, one in each of its p orbitals. O_{2}is**paramagnetic**because it has two unpaired electrons, one in each of its p* orbitals.Is be2 diamagnetic?

Your question is wrong because

**be2**molecule does not exist as**be2**number of electron is 8 so according to MOT its bond order comes out to be zero. Hence**be2**is neither**diamagnetic**nor paramagnetic as it does not exist.