Originally Answered: What is the bond order of F2? Bond order is defined as the difference between the number of bonding electrons divided by 2, and the number of anti-bonding electrons divided by 2. Fluorine molecule, F2, has 18 electrons in total. It has 10 bonding electrons and 8 antibonding electrons.
Moreover, is c2 4 paramagnetic or diamagnetic?
Answers : (1) B2 has 2 unpaired electron so it is predicted to be paramagnetic whereas C2 has only paired electrons so it is predicted to be diamagnetic but not paramagnetic.
Why b2 molecule is paramagnetic?
By constructing a molecular orbital picture for each of the following molecules, determine whether it is paramagnetic or diamagnetic. a. B2 is paramagnetic because it has two unpaired electrons, one in each of its p orbitals. O2 is paramagnetic because it has two unpaired electrons, one in each of its p* orbitals.
Is be2 diamagnetic?
Your question is wrong because be2 molecule does not exist as be2 number of electron is 8 so according to MOT its bond order comes out to be zero. Hence be2 is neither diamagnetic nor paramagnetic as it does not exist.