# How do you solve #3^(2x-1) = 729/9^(x+1)#?

##### 1 Answer

Oct 22, 2015

The solution is

#### Explanation:

First of all, note that all numbers involved are powers of three:

#3=3^1# ;#9=3^2# ;#729 = 3^6# .

So, we can rewrite the equations in terms of powers of three only:

Now use the rule for power of powers:

Now use the rule for dividing powers of a same base:

We're finally in the form